12p^2=10-14p

Solution for 12p^2=10-14p equation:

12p^2=10-14p

We move all terms to the left:

12p^2-(10-14p)=0

We add all the numbers together, and all the variables

12p^2-(-14p+10)=0

We get rid of parentheses

12p^2+14p-10=0

a = 12; b = 14; c = -10;
Δ = b2-4ac
Δ = 142-4·12·(-10)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-26}{2*12}=\frac{-40}{24}
=-1+2/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+26}{2*12}=\frac{12}{24}
=1/2
$